$$ JD = MJD + 240\;000.5 $$
$$ T_{xx} = JCN_{xx} = {JD_{xx} - J2000.0 \over JC} = {JD_{xx} - 245\;1545.0 \over 365\;25 } $$
where JD = Julian Date, MJD = Modified Julian Date, JCN = Julian Century Number
How to compute the Moon's longitude?
$$ T_{TDB} = {JD_{TDB} - 245\;1545.0 \over 365\;25} $$
$$ \lambda_{M} = 218.32 \deg + 481\;267.883T_{TDB} $$
Check below picture.
$$ c = 299\;792\;458\;m/s\;\approx\;300\;000\;km/s\;$$
$$ 1AU = 149\;597\;870\;700\;m \approx 150\;000\;000\;km $$
$$ 1\;pc = 206\;264.806\;247\;096\;AU = 3.26\;ly $$
$$ 1\;ly = 63240\;AU = 9\;460\;000\;000\;000\;km $$
$$ 10\;arcsec \approx 0.002\;78\;deg $$
$$ 1\;rad \approx 57.30\;deg $$
$$ C = (F-32) \times 5/9$$
| Celsius Temp. To Fahrenheit Temp. | Fahrenheit Temp. To Celcius Temp. |
|---|---|
| 40 °C = 104 °F | 104 °F = 40 °C |
| 35 °C = 95 °F | 95 °F = 35 °C |
| 30 °C = 86 °F | 86 °F = 30 °C |
| 25 °C = 77 °F | 77 °F = 25 °C |
| 20 °C = 68 °F | 68 °F = 20 °C |
| 15 °C = 59 °F | 59 °F = 15 °C |
| 10 °C = 50 °F | 50 °F = 10 °C |
| 5 °C = 41 °F | 41 °F = 5 °C |
| 0 °C = 32 °F | 32 °F = 0 °C |
| -5 °C = 23 °F | 23 °F = -5 °C |
| -10 °C = 14 °F | 14 °F = -10 °C |
| -15 °C = 5 °F | 5 °F = -15 °C |
